javax StreamSource 的目的是什么

javax StreamSource的目的

java
import javax.xml.transform.stream.StreamSource;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
public class StreamSourceExample {
    public static void main(String[] args) {
        try {
            // 创建一个StreamSource对象，指定要读取的XML文件
            StreamSource source = new StreamSource("example.xml");
            // 创建一个DocumentBuilder对象
            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();
            // 使用DocumentBuilder对象解析XML文件，返回一个Document对象
            Document document = builder.parse(source.getInputStream());
            // 获取XML文件中的所有节点
            NodeList nodeList = document.getDocumentElement().getChildNodes();
            // 遍历节点并打印内容
            for (int i = 0; i < nodeList.getLength(); i++) {
                Node node = nodeList.item(i);
                if (node.getNodeType() == Node.ELEMENT_NODE) {
                    System.out.println(node.getNodeName() + ": " + node.getTextContent());
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}