javax.xml.bind.UnmarshalException：意外元素（uri：“”

使用javax.xml.bind.UnmarshalException异常解决XML反序列化问题

java
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import java.io.File;
public class XmlUnmarshaller {
    public static void main(String[] args) {
        try {
            // 创建JAXB上下文
            JAXBContext jaxbContext = JAXBContext.newInstance(Student.class);
            // 创建Unmarshaller
            Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
            // 从XML文件中读取数据并反序列化为Java对象
            File xmlFile = new File("student.xml");
            Student student = (Student) unmarshaller.unmarshal(xmlFile);
            // 输出反序列化后的Java对象
            System.out.println(student);
        } catch (JAXBException e) {
            // 处理UnmarshalException异常
            if (e.getLinkedException() instanceof javax.xml.bind.UnmarshalException) {
                javax.xml.bind.UnmarshalException unmarshalException =
                        (javax.xml.bind.UnmarshalException) e.getLinkedException();
                System.out.println("发生UnmarshalException异常：" + unmarshalException.getMessage());
            } else {
                e.printStackTrace();
            }
        }
    }
}

java
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name = "student")
@XmlAccessorType(XmlAccessType.FIELD)
public class Student {
    private String name;
    private int age;
    // getters and setters
}