JAXB：我应该如何整理复杂的嵌套数据结构

如何使用JAXB整理复杂的嵌套数据结构

xml
  
    
      
        
        
        
          
            
              
                
                  
                    
                    
                  
                
              
            
          
        
      
    
  

java
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Student {
    private String name;
    private int age;
    private Courses courses;
    
    // getters and setters
}
@XmlAccessorType(XmlAccessType.FIELD)
public class Courses {
    @XmlElement(name="course")
    private List courseList;
    
    // getters and setters
}
@XmlAccessorType(XmlAccessType.FIELD)
public class Course {
    private String courseName;
    private String grade;
    
    // getters and setters
}

java
public class Main {
    public static void main(String[] args) throws JAXBException {
        // 创建JAXBContext
        JAXBContext jaxbContext = JAXBContext.newInstance(Student.class);
        
        // 创建Unmarshaller
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        
        // 从XML文件中读取数据并转换为Java对象
        Student student = (Student) unmarshaller.unmarshal(new File("student.xml"));
        
        // 输出学生信息
        System.out.println("Name: " + student.getName());
        System.out.println("Age: " + student.getAge());
        System.out.println("Courses:");
        for (Course course : student.getCourses().getCourseList()) {
            System.out.println("  Course Name: " + course.getCourseName());
            System.out.println("  Grade: " + course.getGrade());
        }
        
        // 创建Marshaller
        Marshaller marshaller = jaxbContext.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        
        // 将Java对象转换为XML并写入文件
        marshaller.marshal(student, new File("output.xml"));
    }
}