jdk1.5 中的 javax.xml.bind.JAXBException [java.lang.ClassNotFoundException com.sun

JDK 1.5中的javax.xml.bind.JAXBException [java.lang.ClassNotFoundException: com.sun.xml.bind.v2.ContextFactory] 异常是在使用Java架构绑定（Java Architecture for XML Binding，简称JAXB）时可能遇到的一个错误。JAXB是Java中用于将XML数据与Java对象进行转换的一种技术。

java
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import java.io.File;
public class JAXBExample {
    public static void main(String[] args) {
        try {
            // 创建JAXB上下文
            JAXBContext jaxbContext = JAXBContext.newInstance(Employee.class);
            // 创建Marshaller，用于将Java对象转换为XML
            Marshaller marshaller = jaxbContext.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
            // 创建Unmarshaller，用于将XML转换为Java对象
            Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
            // 创建一个Employee对象
            Employee employee = new Employee();
            employee.setId(1);
            employee.setName("John Doe");
            employee.setAge(30);
            // 将Employee对象转换为XML并保存到文件
            marshaller.marshal(employee, new File("employee.xml"));
            // 从文件中读取XML并转换为Java对象
            Employee unmarshalledEmployee = (Employee) unmarshaller.unmarshal(new File("employee.xml"));
            System.out.println("Unmarshalled Employee: " + unmarshalledEmployee);
        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}
class Employee {
    private int id;
    private String name;
    private int age;
    // 省略getter和setter方法
    @Override
    public String toString() {
        return "Employee{" +
                "id=" + id +
                ", name='" + name + '\'' +
                ", age=" + age +
                '}';
    }
}