JSON.NET 教程 [关闭]

使用JSON.NET进行数据序列化和反序列化的过程非常简单。JSON.NET是一个强大且灵活的开源库，提供了许多功能和选项，使开发人员可以轻松地处理JSON数据。

csharp
public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}
Person person = new Person
{
    Name = "John Doe",
    Age = 30
};
string json = JsonConvert.SerializeObject(person);
Console.WriteLine(json);

json
{"Name":"John Doe","Age":30}

csharp
string json = "{\"Name\":\"John Doe\",\"Age\":30}";
Person person = JsonConvert.DeserializeObject(json);
Console.WriteLine("Name: " + person.Name);
Console.WriteLine("Age: " + person.Age);

Name: John Doe
Age: 30

csharp
string json = "[{\"Name\":\"John Doe\",\"Age\":30},{\"Name\":\"Jane Smith\",\"Age\":20}]";
List people = JsonConvert.DeserializeObject>(json);
var filteredPeople = from p in people
                     where p.Age > 25
                     select p;
foreach (var person in filteredPeople)
{
    Console.WriteLine("Name: " + person.Name);
    Console.WriteLine("Age: " + person.Age);
}

Name: John Doe
Age: 30

csharp
string json = "{\"Name\":\"John Doe\",\"Age\":\"30\"}";
Person person = JsonConvert.DeserializeObject(json);
person.Age = Convert.ToInt32(person.Age);
Console.WriteLine("Name: " + person.Name);
Console.WriteLine("Age: " + person.Age);

Name: John Doe
Age: 30

csharp
string json = "{\"Name\":\"John Doe\"}";
try
{
    Person person = JsonConvert.DeserializeObject(json);
    if (string.IsNullOrEmpty(person.Name))
    {
        throw new Exception("Name is required.");
    }
    Console.WriteLine("Name: " + person.Name);
    Console.WriteLine("Age: " + person.Age);
}
catch (Exception ex)
{
    Console.WriteLine("Error: " + ex.Message);
}

Error: Name is required.