VB FFT - 难以理解结果与频率的关系

VB FFT - 难以理解结果与频率的关系

vb
Imports System.Numerics
Imports MathNet.Numerics.IntegralTransforms
Module FFTExample
    Sub Main()
        ' 输入信号为一组采样值
        Dim samples As Complex() = {New Complex(1, 0), New Complex(2, 0), New Complex(3, 0), New Complex(4, 0)}
        ' 使用MathNet库中的FFT函数进行FFT计算
        Fourier.Forward(samples)
        ' 计算频率分辨率
        Dim sampleRate As Integer = 1000
        Dim frequencyResolution As Double = sampleRate / samples.Length
        ' 输出结果与对应的频率
        For i As Integer = 0 To samples.Length - 1
            Dim frequency As Double = i * frequencyResolution
            Console.WriteLine("频率: " & frequency & " Hz，幅度: " & samples(i).Magnitude)
        Next
    End Sub
End Module