C 将未知大小的数组传递给单个变量中的函数

### 通过指针传递数组到函数中

c
#include 
void processArray(int *arr, int size) {
    for (int i = 0; i < size; i++) {
        printf("%d ", arr[i]);
    }
    printf("%
");
}
int main() {
    int arr1[] = {1, 2, 3, 4, 5};
    int arr2[] = {10, 20, 30};
    int size1 = sizeof(arr1) / sizeof(arr1[0]);
    int size2 = sizeof(arr2) / sizeof(arr2[0]);
    printf("Array 1: ");
    processArray(arr1, size1);
    printf("Array 2: ");
    processArray(arr2, size2);
    return 0;
}