Scala - 从 xml 中完全删除命名空间

scala
import scala.xml._
import scala.xml.transform._
// 定义一个XML字符串
val xmlString = """
  
    Hello
    World
  
"""
// 将XML字符串解析为XML树
val xml = XML.loadString(xmlString)
// 定义一个重写规则，将所有元素的命名空间删除
val removeNamespace = new RewriteRule {
  override def transform(n: Node): Seq[Node] = n match {
    case elem: Elem => elem.copy(scope = TopScope, child = elem.child.flatMap(transform))
    case other => other
  }
}
// 使用重写规则处理XML树
val transformedXml = new RuleTransformer(removeNamespace).transform(xml)
// 打印处理后的XML
println(transformedXml)