Scala：jaxb 或类似的

使用Scala编程语言，我们可以轻松地使用JAXB（Java Architecture for XML Binding）或类似的工具来处理XML数据。JAXB是一种Java API，可以将XML文档与Java对象之间进行转换，使得XML数据的处理更加方便和灵活。在本文中，我们将探讨Scala中使用JAXB的方法，并提供案例代码来说明其用法。

scala
libraryDependencies += "javax.xml.bind" % "jaxb-api" % "2.3.1"
libraryDependencies += "org.glassfish.jaxb" % "jaxb-runtime" % "2.3.1"

scala
import javax.xml.bind.annotation._
@XmlRootElement(name = "person")
@XmlAccessorType(XmlAccessType.FIELD)
class Person {
  @XmlElement var name: String = _
  @XmlElement var age: Int = _
}

scala
import javax.xml.bind._
object JAXBExample {
  def main(args: Array[String]): Unit = {
    val person = new Person()
    person.name = "John Doe"
    person.age = 30
    val context = JAXBContext.newInstance(classOf[Person])
    val marshaller = context.createMarshaller()
    marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true)
    val writer = new StringWriter()
    marshaller.marshal(person, writer)
    val xmlString = writer.toString
    println(xmlString)
  }
}